《輸油管道設(shè)計(jì)與管理》課程設(shè)計(jì)水力計(jì)算程序(共4頁)

精選優(yōu)質(zhì)文檔-----傾情為你奉上 #include<stdio.h> #include<math.h> #define Q 1002.9 //流量,m^3/h; #define D 0.559 //管外徑,m; #define d 0.5384 //管內(nèi)徑,m; #define v 9.028e-6 //運(yùn)動粘度,m^2/s; #define L 1953 //管道全長,Km; #define Zz 1530 //終點(diǎn)海拔高度Zz=1530m; #define ZQ 800 //起點(diǎn)海拔高度ZQ=0m; #define rowt 853.5 //油品在計(jì)算溫度下的密度,Kg/m^3; #define Hsq 0.3e6/(9.81*rowt) //首站進(jìn)站壓力,m水柱; #define Hsz 0.2e6/(9.81*rowt) //末站剩余壓頭,m水液柱; #define hm 10 //站內(nèi)損失,m; main() { double Re, Re1, Re2, E, Qs; double lamda, hl; double A, N; double ai; double H, Hc,V; Qs=Q/3600; V=4*Qs/(3.14*d*d); printf("\n 流速V=%f(m/s)\n\n",V); printf(" 流量Qs=%f(m^3/s)\n\n",Qs); Re=4*1002.9/(3.14*d*3600*v); printf(" 雷諾數(shù)Re=%0.2E\n\n",Re); E=2*0.1/(d*1000); printf(" 相對當(dāng)量粗糙度E=%0.2E\n\n",E); Re1=59.5/pow(E,8.0/7); printf(" 第一邊界雷諾數(shù)Re1=%0.2E\n\n",Re1); Re2=(665-765*log10(E))/E; printf(" 第二邊界雷諾數(shù)Re2=%0.2E\n\n",Re2); /******************************************* ***判斷流態(tài),選用對應(yīng)摩阻計(jì)算公式; ********************************************/ /************如果流態(tài)在層流區(qū)**************/ if(Re<2000) { printf(" /***********************************/\n"); printf(" Re<2000 層流區(qū) \n"); printf(" 層流區(qū)水力摩阻系數(shù)lamda=64/Re;\n\n"); lamda=64/Re; printf(" 水力摩阻系數(shù) lamda=%0.4f\n\n",lamda); printf(" 選用達(dá)西公式計(jì)算沿程阻力損失hl(m)\n"); hl=(lamda*(L*1000)*(V*V))/(d*2*9.81); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); printf(" 選用列賓宗公式計(jì)算沿程阻力損失hl(m)\n"); hl=4.15*Qs*v*(L*1000)/pow(d,4); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); ai=4.15*Qs*v/pow(d,4); printf(" 水力坡降ai=%0.5f\n\n",ai); } /************如果流態(tài)在水力光滑區(qū)**************/ if(3000<Re&&Re<Re1) { printf(" /***********************************/\n"); printf(" 3000<Re<Re1 水力光滑區(qū) \n"); if(Re<10e5) {printf(" 3000<Re<10e5\n"); printf(" 水力摩阻選用lamda=0.3164*pow(Re,-0.25);\n\n"); lamda=0.3164*pow(Re,-0.25); printf(" 水力摩阻系數(shù) lamda=%0.4f\n\n",lamda); printf(" 選用達(dá)西公式計(jì)算沿程阻力損失hl(m)\n"); hl=(lamda*(L*1000)*(V*V))/(d*2*9.81); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); printf(" 選用列賓宗公式計(jì)算沿程阻力損失hl(m)\n"); hl=(0.0246*pow(Qs,1.75)*pow(v,0.25)*(L*1000))/pow(d,4.75); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); ai=0.0246*pow(Qs,1.75)*pow(v,0.25)/pow(d,4.75); printf(" 水力坡降ai=%f\n\n",ai); } else {lamda=(1/(1.81*log10(Re)-1.53))*(1/(1.81*log10(Re)-1.53)); printf(" 水力摩阻系數(shù) lamda=%0.4f\n\n",lamda); printf(" 選用達(dá)西公式計(jì)算沿程阻力損失hl(m)\n"); hl=(lamda*(L*1000)*(V*V))/(d*2*9.81); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); printf(" 選用列賓宗公式計(jì)算沿程阻力損失hl(m)\n"); hl=(0.0246*pow(Qs,1.75)*pow(v,0.25)*(L*1000))/pow(d,4.75); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); ai=0.0246*pow(Qs,1.75)*pow(v,0.25)/pow(d,4.75); printf(" 水力坡降ai=%f\n\n",ai); } }//if(3000<Re&&Re<Re1); /************如果流態(tài)在混合摩擦區(qū)**************/ if(Re1<Re&&Re<Re2) { printf(" /***********************************/\n"); printf(" Re1<Re<Re2 混合摩擦區(qū) \n"); printf(" 水力摩阻選用lamda=0.11*pow((e/(d*1000)+68/Re),0.25);\n\n"); lamda=0.11*pow((E/(d*1000)+98/Re),0.25); printf(" 水力摩阻系數(shù) lamda=%0.4f\n\n",lamda); printf(" 選用達(dá)西公式計(jì)算沿程阻力損失hl(m)\n"); hl=(lamda*(L*1000)*(V*V))/(d*2*9.81); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); printf(" 選用列賓宗公式計(jì)算沿程阻力損失hl(m)\n"); A=pow(10,(0.127*log10(E/(d*1000))-0.627)); hl=(0.0802*A*pow(Qs,1.877)*pow(v,0.123)*(L*1000))/pow(d,4.877); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); ai=0.0802*A*pow(Qs,1.877)*pow(v,0.123)/pow(d,4.877);; printf(" 水力坡降ai=%f\n\n",ai); }//if(Re1<Re&&Re<Re2); /************如果流態(tài)在粗糙區(qū)**************/ if(Re>Re2) { printf(" /***********************************/\n"); printf(" Re>Re2 粗糙區(qū) \n"); printf(" 水力摩阻選用lamda=1/pow((1.74-2*log10(E)),2);\n\n"); lamda=1/pow((1.74-2*log10(E)),2); printf(" 水力摩阻系數(shù) lamda=%0.4f\n\n",lamda); printf(" 選用達(dá)西公式計(jì)算沿程阻力損失hl(m)\n"); hl=(lamda*(L*1000)*(V*V))/(d*2*9.81); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); printf(" 選用列賓宗公式計(jì)算沿程阻力損失hl(m)\n"); N=0.11*pow(E/(d*1000),0.25); hl=(0.0826*N*(Qs*Qs)*(L*1000))/pow(d,5); printf(" 沿程阻力損失hl hl=%0.2E\n\n",hl); ai=0.0826*N*Q*Q/pow(d,5); printf(" 水力坡降ai=%f\n\n",ai); } /************管線全線所消耗的壓力能頭**************/ printf(" /********************************/\n"); printf(" 管線全線所消耗的壓力能頭\n"); printf(" /********************************/\n\n"); H=hl+(Zz-ZQ)+Hsz; printf(" 末站剩余壓頭Hsz=%0.2f(m)\n\n",Hsz); printf(" 管線全線所消耗的壓力能頭H=%0.2f(m)\n\n",H); /*********************************************** ***泵站數(shù)量計(jì)算 ************************************************/ { printf(" /********************************/\n"); printf(" 所需泵站數(shù)量\n"); printf(" /********************************/\n\n"); Hc=2*(386.43-0.*pow(Q,1.75)); printf(" 泵站的揚(yáng)程Hc(m) Hc=%0.2f\n\n",Hc); H=ai*L*1000+(Zz-ZQ)+Hsz; printf(" 全線所需壓頭H(m)H=%0.2f\n\n",H); N=H/(Hc-hm); printf(" 全線布站個(gè)數(shù)N N=%0.1f\n\n",N); N=ceil(H/(Hc-hm)); printf(" 向上取整站數(shù)N N=%0.0f\n\n",ceil(H/(Hc-hm))); } /*********************************************** ***工藝方案經(jīng)濟(jì)計(jì)算，確定最優(yōu)方案 ************************************************/ { double Yguan, Yzhan, Yyun, YY, P; printf(" /********************************/\n"); printf(" 工藝方案經(jīng)濟(jì)計(jì)算，確定最優(yōu)方案\n"); printf(" /********************************/\n\n"); Yguan=2.4*(7.85*3.14*(D*D-d*d)*L*1000/4)*5603; printf(" 管線投資費(fèi)用 Yguan=%0.1f(元)\n\n",Yguan); printf(" 管線投資費(fèi)用 Yguan=%0.3f(億元)\n\n",Yguan/1e8); Yzhan=1.8*(N*3000e4); printf(" 站場投資費(fèi)用 Yzhan=%0.1f(元)\n\n",Yzhan); printf(" 站場投資費(fèi)用 Yzhan=%0.3f(億元)\n\n",Yzhan/1e8); /****************計(jì)算輸油泵功率*****************/ P=1.1*rowt*Qs*Hc/(102*0.807); printf(" 輸油泵站功率 P=%0.2E(Kw)\n\n",P); Yyun=1.0*0.55*N*P*15*350*24; printf(" 運(yùn)營費(fèi)用 Yyun=%0.1f(元)\n\n",Yyun); printf(" 運(yùn)營費(fèi)用 Yyun=%0.3f(億元)\n\n",Yyun/1e8); YY=Yguan+Yzhan+Yyun; printf(" 方案總的經(jīng)濟(jì)費(fèi)用YY=%0.1f(元)\n\n",YY); printf(" 方案總的經(jīng)濟(jì)費(fèi)用YY=%0.3f(億元)\n\n",YY/1e8); } }//main() 專心---專注---專業(yè)